Precision Acoustic Resistance
Posted by: Phill82 on 17 January 2004
Do any of you technical people out there know much about Naim's PAR system and the advantages it is meant to bring?
The title of the final year major project that I'm doing is 'Novel loudspeaker designs', and I thought, being a bit of a Naim speaker fan, that it would be interesting to look at this technique. However there seems to be very little information around on it.
Just incase you don't know what I'm on about, the technique involves spliting the loudspeaker enclosure into two, one small box in which the bass driver is mounted and a larger box which the smaller one vents into via an acoustic resistor.
If you look at it from a low frequency modeling point of view, the acoustic resistance effectively just adds resitance to the driver's own mechanical resistance, thus reducing the Q of the driver and allowing it to be used in an overall enclosure of smaller volume (but with a corresponding reduced low frequency extension). So from this point of view you might as well just design a driver with the correct resistance in the first place and mount it in a single large enclosure. Saying that though, I am asuming that the value of the acoustic resistor is not frequency dependant, so that would probably affect exactly what it does.
However, I'm guessing that there are other reasons why the technique is advantageous other than allowing you to mount a high Q driver in a small box. Does it affect the mid range? I know that mounting the bass driver in a small box is meant to have benifits in terms of box panel resonance, but there are other simplar ways of achieving this that don't use an resistor.
If anyone has any comments or could shed any light on this then that would be very interesting and possibly very useful.
The title of the final year major project that I'm doing is 'Novel loudspeaker designs', and I thought, being a bit of a Naim speaker fan, that it would be interesting to look at this technique. However there seems to be very little information around on it.
Just incase you don't know what I'm on about, the technique involves spliting the loudspeaker enclosure into two, one small box in which the bass driver is mounted and a larger box which the smaller one vents into via an acoustic resistor.
If you look at it from a low frequency modeling point of view, the acoustic resistance effectively just adds resitance to the driver's own mechanical resistance, thus reducing the Q of the driver and allowing it to be used in an overall enclosure of smaller volume (but with a corresponding reduced low frequency extension). So from this point of view you might as well just design a driver with the correct resistance in the first place and mount it in a single large enclosure. Saying that though, I am asuming that the value of the acoustic resistor is not frequency dependant, so that would probably affect exactly what it does.
However, I'm guessing that there are other reasons why the technique is advantageous other than allowing you to mount a high Q driver in a small box. Does it affect the mid range? I know that mounting the bass driver in a small box is meant to have benifits in terms of box panel resonance, but there are other simplar ways of achieving this that don't use an resistor.
If anyone has any comments or could shed any light on this then that would be very interesting and possibly very useful.