A bit of Pythagarus +

Posted by: BigH47 on 08 May 2009

Can the other angles and sides be found with only the 90 degree angle and a hypotenuse of 2 ft(OK 600mm)?

Workings please in case the 600mm needs changing.

I want to put up a post to mount a couple of bird boxes and need to put some supporting braces at the base. So the angle of the cut for the supports are required.

Thanks

Howard
Posted on: 08 May 2009 by Staedtler
Using a^2 = b^2 + c^2
You have, a=600mm, and if you assume b and c are equal then;
600^2 = 2b^2
therefore ((600^2)/2)^0.5 = b = 424.26mm

You can substitute a value for either b or c (here assuming a is still 600mm) to work out the other value
i.e.
b=300mm, then c = 519.62mm.

Hope this helps...
Ian
Posted on: 08 May 2009 by Staedtler
Oh, and I forgot this bit...

If you have a 90degree angle for the post i.e. it sticks straight out of the ground, and the 600mm hypotenuse means it is supported evenly along the ground and up the post, then the angle would be 45degrees for the cut.

If the ground dimension is 350mm, then
600cos (angle) = 350
therefore (angle) = inv cos (350/600) = 54.3degs.
The other angle would then = 180-90-54.3 = 35.69degs.

Have I confused or helped?
Ian
Posted on: 08 May 2009 by BigH47
Thanks guys I'm intending to fix on the stump of a fir, so not sure how much room for the supports if it were 600x600 that would be obvious, just in case I have to do some odd numbers I needed that extra info .
Posted on: 08 May 2009 by Willy
quote:
Originally posted by BigH47:
Can the other angles and sides be found with only the 90 degree angle and a hypotenuse of 2 ft(OK 600mm)?

Workings please in case the 600mm needs changing.

I want to put up a post to mount a couple of bird boxes and need to put some supporting braces at the base. So the angle of the cut for the supports are required.

Thanks

Howard


No. Given only the hypotenuse there are an infinite number of solutions.

Willy.
Posted on: 08 May 2009 by Christopher_M
But Ian's dealt with that by assuming b and c are equal in length.

Chris
Posted on: 08 May 2009 by Willy
Assume nothing. Establish the facts.

Willy.
Posted on: 09 May 2009 by Staedtler
With the basic formula and the second post, infinite solutions can be calculated.
Facts established.
Posted on: 10 May 2009 by Willy
quote:
Originally posted by BigH47:
Can the other angles and sides be found with only the 90 degree angle and a hypotenuse of 2 ft(OK 600mm)?

Howard


No.

If one assumes a length for a second side of the triangle, or a second angle within the triangle then the caluclation can be performed using Pythagoras' theorem (where a length is assumed) or some basic trigonometry (where an angle is assumed).

Willy.
Posted on: 10 May 2009 by deadlifter
Man that`s a long way round to cut a bit of wood for a bird table, why not just use a set square/multi angle square. Unless this is a bit of a joke it`s over complication of a simple task
Confused
Posted on: 10 May 2009 by BigH47
I wasn't trying to over complicate, just seeing if there was a quick(ish) way of getting the angles. I could guess one an then mark up against a vertical post, for the other angle and then make 3 others.
I don't have a multi angle square thingy, hence the question.
No need to turn this into a dissertation.
Posted on: 10 May 2009 by Willy
So long as the two cut ends are perpendicular it'll work.

Willy.