Brain Teasers ? or 50 Years On........... ?
Posted by: Don Atkinson on 02 June 2015
50 Years on…….
50 years ago, I was doing what many 18 year olds are doing this week and over the next few weeks……………….their A-Levels.
Mine were Pure Maths; Applied Maths; Physics and Chemistry. We also had a new subject called The Use of English.
About 10 years ago I started a few “Brain Teaser” threads on this forum. One or two people complained that many of the so-called Brain Teasers were no more than A-Level maths dressed up. That was true of a few teasers, but most were real teasers, especially the ones like “The Ladder” posted by Bam and also the one about the maximum number of 1cm diameter spheres that can be packed into a 10x5x5 cm box.
Any way, never mind Brains or Teasers, I guess one or two other Forumites are also looking back 50 years and would be delighted to tease their brains with calculus, probability, spherical geometry, geometric progressions, Newton’s Laws of Motion ……………………….no ? Then probably best if you drink your weekly 21 units tonight and wake up in the Music Room tomorrow to recover from the nightmare !
First one to follow shortly, and please, please add your own favourites !!
Posted on: 09 September 2015 by ken c
yes, that is what i had in mind for the Pythagorean approach -- you're a mathtype expert now !
the proof with vector manipulation is somewhat less "painful", as follows:
hope you like it as much as i did...
enjoy
ken
Posted on: 14 September 2015 by Don Atkinson
The UK Lottery is now based on selecting 6 numbers from 59.
The probability of winning is now............................?
Posted on: 14 September 2015 by JRHardee
It's been a long time, but I'll rush in with 6!/(59 x 58 x 57 x 55 x 54 x 53)
Posted on: 14 September 2015 by Mulberry
Originally Posted by JRHardee:
It's been a long time, but I'll rush in with 6!/(59 x 58 x 57 x 55 x 54 x 53)
I think you have a typo in here: 6!/(59 x 58 x 57 x 56 x 55 x 54) looks better to me .
My own approach was 6/59 * 5/58 * 4/57 * 3/56 * 2/55 * 1/54 = 0,00000002219, which is just the same.
Posted on: 14 September 2015 by Don Atkinson
Spot-on JRH. (with Mulbery's edit)
If you invert it you get an equally difficult probability to grasp viz 1 in 45,057,474
Which as MDS states in another thread, is about the same as the chances of being struck by lightening.
I'm not sure that's strictly true, but it's in a similar ball-park (or Parish)
Posted on: 14 September 2015 by fatcat
If you've been playing the same numbers every week (from 1 to 49), if you keep doing so, will you have less chance of hitting the jackpot than somebody that randomly picks from the new range of numbers (1 to 59)?
Posted on: 14 September 2015 by JRHardee
Oops...yeah...the typo. Thanks for spotting that.
Posted on: 14 September 2015 by Don Atkinson
Originally Posted by fatcat:
If you've been playing the same numbers every week (from 1 to 49), if you keep doing so, will you have less chance of hitting the jackpot than somebody that randomly picks from the new range of numbers (1 to 59)?
I have a "gut" feeling that you are right.
Deliberately choosing 6 from 49 when the machine is picking 6 from 59 suggests you are denying yourself a big chunk of possibility. But......................
...............are you ?
Posted on: 15 September 2015 by JRHardee
Any single set of six numbers has the same possibility of coming up as any other. Your odds of winning don't change if you choose all new numbers each time, if you pick from a subset, or if you play the same numbers each time, which is the ultimate subset.
Posted on: 21 September 2015 by Don Atkinson
Balls !!!!
Ok, i'm basically on holiday, or rather putting finishing touches to a new home. A busy day but now able to relax. I didn't bring my A-Level maths books with me............. but I thought that a simple problem might keep a few newbies occupied for a few minutes, preferably with their own brain in gear, but I appreciate trawling the internet is the way of the world these days.............
I have 12 spheres (think ball-bearings) that LOOK identical. But one, and only one of them is either heavier or lighter than the others.
I have a pair of scales (think the Scales of Justice) on which I can place any number of spheres to compare their weights, e.g. three on each side - and if they balance, then none of these six is the "odd one out". Such an event would be classed as "a single weighing"
What is the minimum number of weighings I need to perform to identify the "Odd Ball" and determine whether it is light or heavy ?
Obviously a description of the sequence of weighings is required to accompany the answer........
Adam is prohibited, because his method is too clever !!!!
Posted on: 02 November 2015 by Steve J
A simple brain tease.
1 3 5
2 4 ?
Posted on: 03 November 2015 by Don Atkinson
Ok, somebody has to start...............!
Rationality says "its obviously 6 !"
Wisdom says, "that's far too obvious, even though its a 'simple ' brain tease !"
So we eliminate "6"
Posted on: 03 November 2015 by Sneaky SNAIC
Originally Posted by Steve J:
A simple brain tease.
1 3 5
2 4 ?
Pi
Posted on: 03 November 2015 by Steve J
Originally Posted by Don Atkinson:
Ok, somebody has to start...............!
Rationality says "its obviously 6 !"
Wisdom says, "that's far too obvious, even though its a 'simple ' brain tease !"
So we eliminate "6"
Correct. It's not "6". Think laterally.
Posted on: 03 November 2015 by Mulberry
With the most obvious answer out of the way, how about "5"? My train of thought: 1+4=5 (V-pattern), 2+3=5 (inverted V).
Posted on: 03 November 2015 by Tony2011
Is is automotive related?
Posted on: 03 November 2015 by Steve J
Correct.
Posted on: 03 November 2015 by Tony2011
Yep, that's the one. Thinking outside the (gear)box
Posted on: 03 November 2015 by Mulberry
Ah, one of these. At least I can point to my cars 6-speed gearbox as a cheap excuse .
Posted on: 03 November 2015 by Don Atkinson
Drove up to the downs for a walk this morning, to give Steve's teaser a bit of thought.
Drove back more convinced than ever that the answer was going to be "6"
Posted on: 06 November 2015 by Don Atkinson
Subject should be obvious, but the answer shocked me !
50,000
£25,500
92
71
11%
£6.50
Assume 6 weeks plus public holidays
SJ and others can advise and use more accurate numbers where appropriate.
Posted on: 06 November 2015 by Penarth Blues
Originally Posted by Don Atkinson:
Subject should be obvious, but the answer shocked me !
50,000
£25,500
92
71
11%
£6.50
Assume 6 weeks plus public holidays
SJ and others can advise and use more accurate numbers where appropriate.
Junior doctors hourly pay after their 11% rise
Posted on: 06 November 2015 by Don Atkinson
Originally Posted by Penarth Blues:
Originally Posted by Don Atkinson:
Subject should be obvious, but the answer shocked me !
50,000
£25,500
92
71
11%
£6.50
Assume 6 weeks plus public holidays
SJ and others can advise and use more accurate numbers where appropriate.
Junior doctors hourly pay after their 11% rise
well-spotted, Close.
Try the arithmetic.:-
Deduct the 11% proposed increase.
Use 92 hours
Assume 6 weeks plus public holidays
The £6.50 is the current minimum wage
Try it again with 71 hours and the proposed new starting salary - and although it moves to the right side of the minimum wage, even the living wage begins to look attractive !!
Posted on: 06 November 2015 by Steve J
Interesting. Things don't change much over the years. When I was a junior doctor starting out in 1979 I worked out my hourly rate. I used to have two evenings off a week and every other weekend off, all other time was spent in the hospital. My hourly rate of pay was less than 20p an hour.
Queue the Monty Python sketch.
Posted on: 06 November 2015 by Don Atkinson
I imagine Junior Doctors get a bit of time-and-a-half and possibly even double-time for unsociable hours, but even so, these figures are surprising !